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For analyzing grouped data, we follow the same logic described in the
Duane model. If Eqn. (1) is linearized:
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According to Crow [9], the
likelihood function for the grouped data case, (where n1, n2, n3, ..., nk
failures are observed within each group and k
is the number of groups), is:
And
the MLE of λ based
on this relationship is:
(32)where n is the total number of failures from all the groups.
And the estimate of β is the value
that satisfies:
(33)
Crow-AMSAA Example 4
Consider the grouped failure times data given in Table 5.2. Solve for the Crow-AMSAA parameters using MLE.
Table 5.2 - Grouped failure times data
Run |
Cumulative |
End |
ln(Ti) |
ln(Ti)2 |
ln(θi) |
ln(Ti) • ln(θi) |
1 |
2 |
200 |
5.298 |
28.072 |
0.693 |
3.673 |
2 |
3 |
400 |
5.991 |
35.898 |
1.099 |
6.582 |
3 |
4 |
600 |
6.397 |
40.921 |
1.386 |
8.868 |
4 |
11 |
3000 |
8.006 |
64.102 |
2.398 |
19.198 |
|
|
Sum = |
25.693 |
168.992 |
5.576 |
38.321 |
Solution to Crow-AMSAA Example 4
To obtain the estimator of β,
Eqn. (33) must be solved numerically for β.
Using RGA, the value of
is 0.6315. Now plugging this value
into Eqn. (32), the estimator of λ
is:
Therefore, the
intensity function becomes: ![]()