General Examples Using the Duane Model
Duane Example 6
A prototype of a system was tested with design changes incorporated
during the test. A total of 12 failures occurred. The data set is given
in Table 4.5.
- Estimate the Duane parameters.
- Plot the cumulative and instantaneous MTBF curves.
- How many cumulative test and development hours are required to
meet an instantaneous MTBF goal of 500 hours?
- How many cumulative test and development hours are required to
meet a cumulative MTBF goal of 500 hours?
Table 4.5 - Developmental test data for
Example 6
Failure
Number |
Cumulative
Test Time (hr) |
1 |
80 |
2 |
175 |
3 |
265 |
4 |
400 |
5 |
590 |
6 |
1100 |
7 |
1650 |
8 |
2010 |
9 |
2400 |
10 |
3380 |
11 |
5100 |
12 |
6400 |
Solution to Duane Example 6
- Figure 4.11 shows the data entered
into RGA along
with the estimated Duane parameters.
- Figure 4.12 shows the cumulative
and instantaneous MTBF curves.
- Figure 4.13 shows the cumulative test and development
hours needed for an instantaneous MTBF goal of 500 hours.
- Figure 4.14 shows the cumulative
test and development hours needed for a cumulative MTBF goal of 500
hours.

Figure
4.11: Entered data and the estimated Duane parameters |

Figure
4.12: The cumulative and instantaneous MTBF curves |

Figure
4.13: Required test time for an instantaneous MTBF of 500 hours |

Figure
4.14: Required test time for a cumulative MTBF of 500 hours |
Duane Example 7
Two identical systems
were tested. Any design changes made to improve the reliability of these
systems were incorporated into both systems when any system failed. A
total of 29 failures occurred. The data set is given in Table 4.6. Do
the following:
- Estimate the Duane parameters.
- Assume both units are tested for an additional 100 hrs each. How
many failures do you expect in that period?
- If testing/development were halted at this point, what would the
reliability equation for this system be?
Table 4.6 - Developmental
test data |
Failure
Number |
Failed
Unit |
Test Time
Unit 1 (hr) |
Test Time
Unit 2 (hr) |
| 1 |
1 |
0.2 |
2.0 |
| 2 |
2 |
1.7 |
2.9 |
| 3 |
2 |
4.5 |
5.2 |
| 4 |
2 |
5.8 |
9.1 |
| 5 |
2 |
17.3 |
9.2 |
| 6 |
2 |
29.3 |
24.1 |
| 7 |
1 |
36.5 |
61.1 |
| 8 |
2 |
46.3 |
69.6 |
| 9 |
1 |
63.6 |
78.1 |
| 10 |
2 |
64.4 |
85.4 |
| 11 |
1 |
74.3 |
93.6 |
| 12 |
1 |
106.6 |
103 |
| 13 |
2 |
195.2 |
117 |
| 14 |
2 |
235.1 |
134.3 |
| 15 |
1 |
248.7 |
150.2 |
| 16 |
2 |
256.8 |
164.6 |
| 17 |
2 |
261.1 |
174.3 |
| 18 |
2 |
299.4 |
193.2 |
| 19 |
1 |
305.3 |
234.2 |
| 20 |
1 |
326.9 |
257.3 |
| 21 |
1 |
339.2 |
290.2 |
| 22 |
1 |
366.1 |
293.1 |
| 23 |
2 |
466.4 |
316.4 |
| 24 |
1 |
504 |
373.2 |
| 25 |
1 |
510 |
375.1 |
| 26 |
2 |
543.2 |
386.1 |
| 27 |
2 |
635.4 |
453.3 |
| 28 |
1 |
641.2 |
485.8 |
| 29 |
2 |
755.8 |
573.6 |
|
Solution to Duane Example 7
- Figure 4.15 shows the data entered into RGA
along with the estimated Duane parameters.

Figure
4.15: Entered data and the estimated parameters |
- The current accumulated test time for both units is 1329.4 hr.
If the process were to continue for an additional combined time of
200 hr, the expected cumulative number of failures at T = 1529.4
is 31.2695, as shown in Figure 4.16. At T
= 1329.4, the expected number of failures is 29.2004. Therefore, the
expected number of failures that would be observed over the additional
200 hr is 31.2695 - 29.2004 = 2.0691 ≈ 2.
- If testing/development were halted at this point, the system failure
intensity would be equal to the instantaneous failure intensity at
that time, or λ = 0.0107 failures/hr. See Figure 4.17.
An exponential distribution can be assumed since the value of the
failure intensity at that instant in time is known. Therefore:

Weibull++
can be utilized (from within RGA) to provide a Reliability vs. Time plot.
This is shown in Figure 4.18.

Figure
4.16: The expected cumulative number of failures at T = 1529.4 |

Figure
4.17: Calculate the instantaneous failure intensity at the end
of the test |

Figure
4.18: Reliability vs. Time plot |
Duane Example 8
Given the sequential
success/failure data in the Table 4.7, do the following:
- Estimate the Duane parameters.
- What is the instantaneous MTBF at the end of the test?
- How many additional test runs with a one-sided 90% confidence level
are required to meet an instantaneous MTBF goal of 5 hours?
Table 4.7 - Sequential
data for Example 8 |
Run
Number |
Result |
| 1 |
F |
| 2 |
F |
| 3 |
S |
| 4 |
S |
| 5 |
S |
| 6 |
F |
| 7 |
S |
| 8 |
F |
| 9 |
F |
| 10 |
S |
| 11 |
S |
| 12 |
S |
| 13 |
F |
| 14 |
S |
| 15 |
S |
| 16 |
S |
| 17 |
S |
| 18 |
S |
| 19 |
S |
| 20 |
S |
|
Solution to Duane Example 8
- Figure 4.19 shows the data set entered
into RGA along with the estimated Duane parameters.
- The MTBF at the end of the test is equal to 4.5904 hours. Note
that this is the DMTBF that is shown in the Control Panel in Figure
4.20.
- Figure 4.20 shows the number of test runs
with both one-sided confidence bounds at 90% confidence level to achieve
an instantaneous MTBF of 5 hours. Therefore, the number of additional
test runs required with a 90% confidence level is equal to 42.2481
- 20 = 22.2481 ≈ 23 test runs.

Figure
4.19: Entered data and the estimated parameters |

Figure
4.20: Number of test runs with a one-sided 90% confidence
level required to meet an instantaneous MTBF goal of 5 hours |